
g(x) = ∫ from a to x f(t)dt is an accumulation function. It accumulates area.
Key properties:
g'(x) = f(x) (by FTC Part 2)
g''(x) = f'(x)
g(a) = 0 (integral from a to a)
Given a graph of f:
Where is g increasing? Where f > 0 (positive area accumulating).
Where is g decreasing? Where f < 0 (negative area accumulating).
Where does g have a max? Where f crosses from positive to negative.
Where does g have inflection points? Where f has extrema.
AP exam loves this. "Given the graph of f, find g(4) where g(x) = ∫ from 0 to x f(t)dt." Calculate the area under f from 0 to 4 using geometry (triangles, rectangles).
Reference:
TaskLoco™ — The Sticky Note GOAT